AM TRANSMITTER

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AM TRANSMITTER In an  AM  ( amplitude modulation )  transmitter  the amplitude (strength) of the carrier wave is varied in proportion to the modulation signal. In an FM (frequency modulation)  transmitter  the frequency of the carrier is varied by the modulation signal. There are two basic configuration for transmitters. High level modulation low level modulation  High level modulation In high power modulation signal,the carrier voltage is modulated at highest power level.the require power level is obtained by class c power amplifier.The block diagram of high level modulation as shown in fig(a). low level modulation In the low level modulation system, the carrier is modulated at low power level and the carrier power is subsequently raised to the desire level in the class B amplifier . transmitters using high power level are widely use at present .The block diagram of high level modulation as shown in fig(b). advantage AM sign

H TYPE T JUNCTION (H PLANE TEE)

H TYPE TEE JUNCTION

An H type T junction its so in figure (A) it is called an  H type T Junction because the long axis of the b r is parallel to the plane of the magnetic lines of the force in the waveguide full stop again comma for simplicity, only  the E lines    are show in figure.It X indicates an E line Moving away from the observer.  Each dot indicates an E line is moving toward the observer.
In view (1) of figure(B),the signal fed into arm b and in phase outputs are obtained from the a and c and the output signal is obtained from the b arm because the fields add at the junction and induce E lines into the b arm. If 180 degree out of phase signals are fed into arms a and c, as shown in view (3),no output is obtained fro b arm because the opposing fields cancel at the junction .if a signal is fed into the a arm, as shown in view (4), outputs will be obtained from the b and c arms .the reverse is also true. If a signal is fed into the c arm, outputs will be obtained from  the a and b arms.



S MATRIX OF H TYPE TEE PLANE 
We know that,
When TE
10 mode is made to propagate into port 3 the two outputs at port 1 & port 2 will have a output equal in phase
Since it is a three port junction the s-matrix can be derived as follows.

Step 1: Scattering coefficient (plane of symmetry)
S23= S13 ------- (1)
the outputs at ports 1 and port 2  with an input at port 3 will be equal in phase
Step 2: If port 3 is perfectly matched to the junction
S33 = 0 -------- (2)
Step 3: From symmetric property
Sij = Sji
S12 = S21
S13 = S31
S23 = S32=S13 --------- (3)

Using values of equation 1, 2, 3 in S matrix, it becomes:

 --- (4)
Step 4: From unitary property  

i.e
R1C1: |S11 |2 + |S12|2 + |S13|2 = 1 -------- (5)
R2C2: |S12|2 + |S22|2 + |S13|2 = 1 --------- (6)
R3C3: |S13|2 + |S13|2 = 1 --------- (7)
R3C1: S13.S11* + S13.S12* = 0 ---------- (8)

Equating (5) & (6), we get,
|S11 |2 + |S12|2 + |S13|2=|S12|2 + |S22|2 + |S13|2
               S11 = S22 ---------- (9)
From equation (7) S13 =   --------- (10)
From equation (8), S13 (S11* + S12*) = 0
Or S11 = -S12  or S12=-S11----------from (9) ------- (11)
Using equation (9), (10) & (11) in equation (5) |S11|2 + |S11|2 +   = 1
Or 2|S11|2 =   or S11 =   --------- (12)
S12=(-1/2)
S22=(1/2) ---------- (13)
Substitute all these values in S-matrix

We know that [b] = [S] [a]

 ---------- (14)
 ---------- (15)

 ---------- (16)

 ---------- (17)
Case 1: a1=a2=0, a3≠ 0
i.e Input at Port 3 and no input at port1 and port 2
Put case 1 values in equation 15, 16, 17:

  H TYPE TEE JUNCTION WITH S MATRIX.


















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